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2000x^2+150000x=0
a = 2000; b = 150000; c = 0;
Δ = b2-4ac
Δ = 1500002-4·2000·0
Δ = 22500000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500000000}=150000$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150000)-150000}{2*2000}=\frac{-300000}{4000} =-75 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150000)+150000}{2*2000}=\frac{0}{4000} =0 $
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